एक ऊँची इमारत से एक गेंद 9.8 मीटर/सेकण्ड के एक समान त्वरण के साथ गिरायी जाती है 3 सैकण्ड के बाद वेग क्या होगा ? - A ball is dropped from a tall building with a uniform acceleration of 9.8 m/s, what will be the velocity after 3 seconds? - Ek Unchi Imarat Se Ek Gend 9 . 8 Mee / Second Ke Ek Saman Twarann Ke Sath girayi Jati Hai 3 Second Ke Baad Veg Kya Hoga ? General Science in hindi, Physics 9 . 6 Mee / Se question answers in hindi pdf 29 . 4 Mee / Se questions in hindi, Know About 9 . 8 Mee / Se General Science online test General Science notes in hindi quiz book 39 . 3 Mee / Se
गलत उतर है
Please.give complete solution.
9.8 m per second square hona chahiye. Nahi to velocity ho jayega aur other answers aayega
Twaran ko Meter/Sec2 me likha jata hai. Aapne jo twaran diya hai woh velocity ko pradarshit kar raha hai. Vaseem
V=u+at V=9.8+9.83 V=(1+3)9.8 V=4 9.8=39.2
29.4 m/s
Explanation V=ut+1/2 gt2
29.4meter per second hota h
29.4meter per second hota h
गलत है उतर
Sole plzz